Answer
$ v_d = 1.02* 10^{-14} m/s$
Work Step by Step
We have
$ i = \frac{q}{t}$
$ i = \frac{n_e*e}{t}$
$ i = \frac{n_e*e}{5}$
also we have
$i = n_e*A*v_{d}$
$\implies i = \frac{n_e*e}{5} = n_e*A*v_d$
$\implies \frac{e}{5} = A* v_d$
$\implies v_d = \frac{e}{5* \pi*r^2}$
$\implies v_d = \frac{1.6*10^{-19}}{5* 3.14*(10^{-3})^2} m/s$
$\implies v_d = 1.02* 10^{-14} m/s$