Answer
$I = 1.8\times 10^{-8}~A$
Work Step by Step
We can find the average current:
$I = \frac{Q}{t}$
$I = \frac{9.0\times 10^{-12}~C}{0.50\times 10^{-3}~s}$
$I = 1.8\times 10^{-8}~A$
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