Chapter 30 - Current and Resistance - Exercises and Problems - Page 887: 19

$1.68\;\rm A$

We know that the current density is given by $$J=\sigma E=\dfrac{I}{A}$$ So, $$I=\sigma_{Al} E A$$ Plug the known; using Table 30.2 $$I=(3.5\times 10^7)(0.012)(4\times 10^{-6})$$ $$I=\color{red}{\bf 1.68}\;\rm A$$