Answer
(a) $T_1=122K;T_2=366K$
(b) Isobaric
(c) $3atm$
Work Step by Step
(a) We know that
$T_1=\frac{p_1V_1}{nR}$
We plug in the known values to obtain:
$T_1=\frac{(101300)(0.001)}{(0.1)(8.31)}$
This simplifies to:
$T_1=122K$
Now $T_2=3T_1$
$\implies T_2=3(122)=366K$
(b) We know that the pressure is constant during the process, therefore, the process is isobaric.
(c) We know that
$p_3=\frac{V_2}{V_1}p_2$
We plug in the known values to obtain:
$p_3=\frac{3000}{1000}(1)$
$\implies p_3=3atm$
