Answer
$8.93\times 10^{-3}moles$
Work Step by Step
We can determine the required number of moles as follows:
$\Delta n=\frac{p_aV}{RT_{\circ}}(1-\frac{T_{\circ}}{T_1})$
We plug in the known values to obtain:
$\Delta n=(\frac{101300\times 0.001}{8.31\times 293})(1-\frac{293}{373})$
This simplifies to:
$\Delta n=0.00893moles=8.93\times 10^{-3}moles$
