Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 466: 49

Answer

$155cm^3$

Work Step by Step

We can determine the required volume of the gas as follows: $V^{\prime}=\frac{p_a}{p_a+\rho gh}V$ We plug in the known values to obtain: $V^{\prime}=\frac{101300}{101300+(1000)(9.8)(3)}$ This simplifies to: $V^{\prime}=155cm^3$
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