Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 466: 52

Answer

$1.066cm$

Work Step by Step

We can determine the required diameter as follows: $d_2=d_1\sqrt{(1+\frac{\rho g}{p_a})\frac{T_2}{T_1}}$ We plug in the known values to obtain: $d_2=1\sqrt{(1+\frac{1000(9.8)}{101300})(\frac{293}{283})}$ This simplifies to: $d_2=1.066cm$
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