Answer
$1.066cm$
Work Step by Step
We can determine the required diameter as follows:
$d_2=d_1\sqrt{(1+\frac{\rho g}{p_a})\frac{T_2}{T_1}}$
We plug in the known values to obtain:
$d_2=1\sqrt{(1+\frac{1000(9.8)}{101300})(\frac{293}{283})}$
This simplifies to:
$d_2=1.066cm$