Answer
$68.25K$
Work Step by Step
We can find the freezer temperature as
$\frac{p_1}{T_1}=\frac{p_2}{T_2}$
This can be rearranged as:
$T_2=\frac{p_2}{p_1}T_1$
We plug in the known values to obtian:
$T_2=\frac{30}{120}(273)$
$\implies T_2=68.25K$