Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 16 - A Macroscopic Description of Matter - Exercises and Problems - Page 466: 50

Answer

$68.25K$

Work Step by Step

We can find the freezer temperature as $\frac{p_1}{T_1}=\frac{p_2}{T_2}$ This can be rearranged as: $T_2=\frac{p_2}{p_1}T_1$ We plug in the known values to obtian: $T_2=\frac{30}{120}(273)$ $\implies T_2=68.25K$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.