Answer
Therefore the final temperature of the aluminum is 32.8$^{\circ}$C.
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
67.4 = (265.95) (0.9) ($\Delta t $)
***We multiply 265.95 times 0.9 and then divide 67.4 by that answer
*** solve using a calculator
$ \Delta t = 0.2810 ^{\circ} $
Therefore the temperature change is $0.2810^{\circ}$
The initial temp is 32.5 so the final temp= initial temp + $ \Delta t$
= 32.5 + 0.2810 = 32.8.
Therefore the final temperature is 32.8$^{\circ}$C.
