Answer
Therefore the temperature required is $9.0 \times 10^{3}$ J
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
q = (65 g) (4.18) (33)
*** solve using a calculator
q= $9.0 \times 10^{3}$ J