Answer
Therefore the final temperature is $30.8^{\circ}$
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
15 = (12) (0.444) ($\Delta t $)
***We multiply 12 times 0.444 and then divide 15 by that answer
*** solve using a calculator
$ \Delta t = 2.81^{\circ} $
Therefore the temperature change is $3.7^{\circ}$
The initial temp is 28 so the final temp= initial temp + $ \Delta t$
= 28 + 2.81 = 30.8
