Answer
Therefore the amount of heat absorbed is 70.74 J
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
q = (30.3) (0.129) (18.1)
*** solve using a calculator
q= 70.74 J
Therefore the heat required is 70.74 J