Answer
Therefore the specific heat capacity is 0.235 J/g$^{\circ}$C and thus, the metal is silver, as the specific heat capacity of silver is 0.235 J/g$^{\circ}$C.
Work Step by Step
We will use the equation $q=mc\Delta t$
q = heat transferred
m = mass
c = specific heat
$\Delta t $ = change in temperature
plug in the values.
58 = (28) (c) (8.8)
***We multiply 28 times 8.8 and then divide 58 by that answer
*** solve using a calculator
c= 0.235
Therefore the specific heat capacity is 0.235 J/g$^{\circ}$C and thus, the metal is silver, as the specific heat capacity of silver is 0.235 J/g$^{\circ}$C.
