General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Questions and Problems - Page 120: 3.50

Answer

61.1% isopropyl l alcohol

Work Step by Step

1. take the mass of the isopropyl alcohol and divide it by the weight of the aqueous solution 3.67g/6.01g= 0.6106g 2. take 0.6106g and multiply that by 100 to know the percent of isopropyl alcohol in the aqueous solution 0.6106g x 100= 61.06% 3. round your answer to 3 significant figures since there are three significant figures in each of masses provided 61.06% rounded to three significant figures= 61.1%
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