Answer
Mass of 0.543 mol $H_{3}BO_{3}$ is 33.6 g
Work Step by Step
Mass of 0.543 mol $H_{3}BO_{3}$
Strategy: We have to convert moles to mass. So the conversion factor is Molar mass/ 1 mol.
Molar mass of $H_{3}BO_{3}$= 3 x 1.00 + 1x 10.81 + 3 x 15.999
Molar mass of $H_{3}BO_{3}$= 61.8 g/mol
0.543 mol $H_{3}BO_{3}$ x $\frac{61.8g}{1 mol}$ = 33.56 g
Mass of 0.543 mol $H_{3}BO_{3}$ is 33.6 g ( to three significant figures)
