General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Questions and Problems - Page 120: 3.55

Answer

Mass percentage of Al in the sample of alloy is 72.3 % . Mass percentage of Mg in the sample of alloy is 27.7 %

Work Step by Step

Strategy: Convert moles to mass by using conversion factor Molar mass/ 1 mol. Then find the total mass of the alloy by adding the masses of Al and Mg. Lastly find the mass percentage of Al and Mg in the alloy. 1- Mass of 0.0898 mol Al Molar mass of Al= 26.981 g/mol 0.0898 mol Al x $\frac{26.981g}{1 mol}$ =2.4229 g Mass of 0.0898 mol Al is 2.4229 g. Mass of 0.0381 mol Mg Molar mass of Mg= 24.305 g/mol 0.0381 mol Mg x $\frac{24.305g}{1 mol}$ =0.9260 g Mass of 0.0381 mol Mg is 0.9260 g. 2- The total mass of alloy is: mass Al + mass Mg. So the total mass is 2.4229 g + 0.9260 g = 3.3489 g. 3- Mass percentage of Al in the sample of alloy = $\frac{2.4229 g (Al )}{3.3489(sample of alloy)}$ $\times$ 100% Mass percentage of Al in the sample of alloy = 0.72348 $\times$ 100% Mass percentage of Al in the sample of alloy is 72.3 % ( to three significant figures). Mass percentage of Mg in the sample of alloy = $\frac{0.926 g (Mg)}{3.3489(sample of alloy)}$ $\times$ 100% Mass percentage of Mg in the sample of alloy = 0. 2765 $\times$ 100% Mass percentage of Mg in the sample of alloy is 27.7 % ( to three significant figures).
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