## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 6 - Electronic Structure of Atoms - Exercises: 6.49

#### Answer

The velocity of the neutron needed is $v=3.165\times10^3m/s$.

#### Work Step by Step

*The de Broglie relationship: $$\lambda=\frac{h}{mv}$$ $\lambda$: wavelength of object $h$: Planck's constant ($h=6.626\times10^{-34} J.s$) $m$: mass of object $v$: velocity of object 1) Find the known variables - Wavelength of the neutron: $\lambda=1.25{\buildrel _{\circ} \over {\mathrm{A}}}=1.25\times10^{-10}m$ - Mass of the neutron: $m\approx1.675\times10^{-27}kg$ 2) Calculate the velocity of the neutron $v=\frac{h}{m\lambda}=\frac{6.626\times10^{-34}}{(1.675\times10^{-27})\times(1.25\times10^{-10})}\approx3.165\times10^{3}m/s$

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