## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 6 - Electronic Structure of Atoms - Exercises: 6.47a

#### Answer

The wavelength of the skiing person is $\lambda=5.613\times10^{-37}m$.

#### Work Step by Step

*The de Broglie relationship: $$\lambda=\frac{h}{mv}$$ $\lambda$: wavelength of object $h$: Planck's constant ($h=6.626\times10^{-34} J.s$) $m$: mass of object $v$: velocity of object 1) Find the known variables - Mass of person: $m=85kg$ - Velocity of the person: $v=50km/h=5\times10^4m/h\approx13.889m/s$ 2) Calculate the wavelength of the skiing person $$\lambda=\frac{h}{mv}=\frac{6.626\times10^{-34}}{85\times13.889}\approx5.613\times10^{-37}m$$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.