Answer
The wavelength of the bullet is $\lambda=2.65\times10^{-34}m$.
Work Step by Step
*The de Broglie relationship: $$\lambda=\frac{h}{mv}$$
$\lambda$: wavelength of object
$h$: Planck's constant ($h=6.626\times10^{-34} J.s$)
$m$: mass of object
$v$: velocity of object
1) Find the known variables
- Mass of the bullet: $m=10.0g=10^{-2}kg$
- Velocity of the bullet: $v=250m/s$
2) Calculate the wavelength of the bullet
$$\lambda=\frac{h}{mv}=\frac{6.626\times10^{-34}}{10^{-2}\times250}\approx2.65\times10^{-34}m$$
