Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.36a

Answer

Statement (i) and statement (iii) are true.

Work Step by Step

Let's go through each statement: (i) First, emitting light means emitting energy, so the hydrogen electron must go to a lower state with a lower energy, or in this case, only n = 1 or n = 2. Going to n = 1 and going to n = 2 would release two different photons with two different energies, since the difference in energy between n = 3 and n = 1 is different from that between n = 3 and n = 2. Therefore, light at two and only two specific and different wavelengths could be emitted. (i) is true. (ii) You just have to remember: the higher the state, the higher the energy. So, a hydrogen atom in the n = 2 state is at a higher energy than the n = 1 state (ii) is false. (iii) If an electron moves from a higher state (higher energy) to a lower state (lower energy), it will emit a photon with an energy equal to the difference in energy between the two states involved. (iii) is true.
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