#### Answer

Statement (i) and statement (iii) are true.

#### Work Step by Step

Let's go through each statement:
(i) First, emitting light means emitting energy, so the hydrogen electron must go to a lower state with a lower energy, or in this case, only n = 1 or n = 2. Going to n = 1 and going to n = 2 would release two different photons with two different energies, since the difference in energy between n = 3 and n = 1 is different from that between n = 3 and n = 2. Therefore, light at two and only two specific and different wavelengths could be emitted.
(i) is true.
(ii) You just have to remember: the higher the state, the higher the energy. So, a hydrogen atom in the n = 2 state is at a higher energy than the n = 1 state
(ii) is false.
(iii) If an electron moves from a higher state (higher energy) to a lower state (lower energy), it will emit a photon with an energy equal to the difference in energy between the two states involved.
(iii) is true.