Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.58b

Answer

There are 5 possible orbitals with the values: - $n=5$, $l=2$, $m_l=-2$ - $n=5$, $l=2$, $m_l=-1$ - $n=5$, $l=2$, $m_l=0$ - $n=5$, $l=2$, $m_l=1$ - $n=5$, $l=2$, $m_l=2$

Work Step by Step

*NOTES TO REMEMBER: In an orbital designation, - the number represents the value of $n$. - the letter represents the value of $l$, according to the following rule: $l=0$, the letter used is $s$. $l=1$, the letter used is $p$. $l=2$, the letter used is $d$. $l=3$, the letter used is $f$. The subshell is $5d$. Therfore, $n=5$ and $l=2$. For $l=2$, there are 5 possible orbitals corresponding to 5 possible values of $m_l$: $m_l=[-2,-1,0,1,2]$.
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