Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Exercises: 6.58a

Answer

There are 3 possible orbitals with the values: - $n=2$, $l=1$, $m_l=-1$ - $n=2$, $l=1$, $m_l=0$ - $n=2$, $l=1$, $m_l=1$

Work Step by Step

*NOTES TO REMEMBER: In an orbital designation, - the number represents the value of $n$. - the letter represents the value of $l$, according to the following rule: $l=0$, the letter used is $s$. $l=1$, the letter used is $p$. $l=2$, the letter used is $d$. $l=3$, the letter used is $f$. The subshell is $2p$. Therefore, $n=2$ and $l=1$. For $l=1$, there are 3 possible orbitals corresponding to 3 possible values of $m_l$: $m_l=[-1,0,1]$.
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