Answer
The energy of the photon is $$E\approx4.366\times10^{-19}J$$
Work Step by Step
The energy of the photon is calculated according to the formula $$E=h\frac{c}{\lambda}$$
Here,
Planck's constant $h\approx6.626\times10^{-34}J.s$
The speed of light in a vacuum $c\approx2.998\times10^8m/s$
The wavelength of the absorbed photons $\lambda=455nm=4.55\times10^{-7}m$
Therefore, the energy of the photon is $$E=\frac{(6.626\times10^{-34}J.s)\times(2.998\times10^8m/s)}{4.55\times10^{-7}m}$$$$E\approx4.366\times10^{-19}J$$
