## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 6 - Electronic Structure of Atoms - Additional Exercises: 6.85a

#### Answer

The frequency of the mentioned light is $\nu\approx9.369\times10^{14}s^{-1}$

#### Work Step by Step

The frequency of light is calculated according to the formula $$\nu=\frac{c}{\lambda}$$ $\nu$: frequency of light $c$: speed of light in vacuum $(c\approx2.998\times10^8m/s)$ $\lambda$: wavelength of light Here the wavelength of light $\lambda=320nm=3.2\times10^{-7}m$ So, the frequency of light is $$\nu=\frac{c}{\lambda}$$$$\nu=\frac{2.998\times10^8m/s}{3.2\times10^{-7}m}\approx9.369\times10^{14}s^{-1}$$

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