# Chapter 6 - Electronic Structure of Atoms - Additional Exercises: 6.83a

There are 4 elements which would emit radiatio in the visible part of the spectrum: Ba, Ca, K and Na.

#### Work Step by Step

The wavelength range of the visible part of the electromagnetic spectrum is from $400nm$ to $750nm$. Now we compare the characteristic wavelengths of the elements with the wavelength range of the visible part to see which wavelength fits in the range. There are 4 elements whose characteristic wavelengths fit in the range of the visible part: Ba $(455.4nm)$, Ca $(422.7nm)$, K $(404.7nm)$ and Na $(589.6nm)$ These are the elements which would emit radiation in the visible part of the spectrum.

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