## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 6 - Electronic Structure of Atoms - Additional Exercises: 6.85c

#### Answer

Photons of UV-B radiation are more energetic than photons of UV-A radiation.

#### Work Step by Step

According to the formula $$E=h\nu=h\frac{c}{\lambda}$$ we find that $E$ is inversely proportional with $\lambda$. That means the lower the wavelength of the light, the higher the energy of its photons, and vice versa. So, since the range of wavelength of UV-B radiation is lower than that of UV-A radiation, photons of UV-B radiation are more energetic than photons of UV-A radiation.

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