Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 6 - Electronic Structure of Atoms - Additional Exercises: 6.88a

Answer

The value of $\nu_0$ is $5.531\times10^{14}s^{-1}$.

Work Step by Step

$s^{-1}$ is the unit of frequency here. So, this question in fact asks for the frequency $(\nu)$ of the light with $\lambda=542nm=5.42\times10^{-7}m$ The frequency of that light is calculated according to the formula $$\nu=\frac{c}{\lambda}$$(c is the speed of light in a vacuum, $c\approx2.998\times10^8m/s$)$$\nu=\frac{2.998\times10^8m/s}{5.42\times10^{-7}m}$$$$\nu\approx5.531\times10^{14}s^{-1}$$ So the value of $\nu_0$ is $5.531\times10^{14}s^{-1}$.
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