Answer
The energy of $0.10mol$ of the emitted photons is $$E\approx2.031\times10^4J$$
Work Step by Step
We would use the following formula $$E_p=h\nu$$ to calculate the energy of an emitted photon.
$E_p$: energy of an emitted photon
$h$: Planck's constant $(h\approx6.626\times10^{-34}J.s)$
$\nu$: frequency of the emitted light
1) The frequency of the emitted light is $\nu\approx5.09\times10^{14}s^{-1}$
So, the energy of an emitted photon is $$E_p=h\nu$$$$E_p=(6.626\times10^{-34}J.s)\times(5.09\times10^{14}s^{-1})$$$$E_p\approx3.373\times10^{-19}J$$
2) $1mol$ equals to $6.02\times10^{23}$ photons.
So, $0.10mol$ equals to $0.10\times(6.02\times10^{23}photons)=6.02\times10^{22}$ photons.
Therefore, the energy of $0.10mol$ of the emitted photons is $$E=(6.02\times10^{22}photons)\times E_p$$$$E=(6.02\times10^{22}photons)\times(3.373\times10^{-19}J/photon)$$$$E\approx2.031\times10^4J$$
