## Chemistry: The Central Science (13th Edition)

There are 100g of water in the calorimeter and the temperature rises from 21.6 to 37.8 C. The specific heat of water is 4.18 J/g*K so first we need to find the $\Delta T = 37.8 - 21.6 = 16.2 C$. Since a $\Delta T$ of 1 C is equivalent to a change of 1K then we can write 16.2C as 16.2K. Then, to find how much energy is released we do the following: 4.18 J/g*K * 100g * 16.2K = 6771.6 J Then to convert to kJ we divide by 1000: 6.772 kJ