## Chemistry: The Central Science (13th Edition)

$\Delta H$ = -630 kJ
C6H6 --&gt; 3 C2H2 $\Delta H = + 630 kJ$ If we want to find the enthalpy change for the reverse reaction, we would need to multiply the enthalpy by negative 1 since we are reversing the direction. This means $\Delta H$ = -1 * 630kJ = -630 kJ