## Chemistry: The Central Science (13th Edition)

2 CH3OH + 3 O2 --&gt; 2 CO2 + 4 H2O $\Delta H = -1453 kJ$
CH3OH + 3/2 O2 --&gt; CO2 + 2H2O If we want to write this with whole number coefficients, we need to get rid of the 3/2. In order to do this, we multiply it by 2 to give 3, but then we need to multiply all of the other coefficients by 2 as follows: 2 CH3OH + 3 O2 --&gt; 2 CO2 + 4 H2O . Since we doubled the coefficients, we must also double the $\Delta H$ so that $\Delta H$ = 2 * -726.5 kJ = -1453 kJ