## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 5 - Thermochemistry - Exercises: 5.47b

#### Answer

2 CH3OH + 3 O2 --> 2 CO2 + 4 H2O $\Delta H = -1453 kJ$

#### Work Step by Step

CH3OH + 3/2 O2 --> CO2 + 2H2O If we want to write this with whole number coefficients, we need to get rid of the 3/2. In order to do this, we multiply it by 2 to give 3, but then we need to multiply all of the other coefficients by 2 as follows: 2 CH3OH + 3 O2 --> 2 CO2 + 4 H2O . Since we doubled the coefficients, we must also double the $\Delta H$ so that $\Delta H$ = 2 * -726.5 kJ = -1453 kJ

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