## Chemistry: The Central Science (13th Edition)

$\Delta H = + 726.5 kJ$
Given the reaction : CH3OH + 3/2 O2 --> CO2 + 2 H2O $\Delta H = -726.5 kJ$ In order to find the enthalpy change for the reverse reaction, we must multiply the enthalpy by -1 Therefore, the enthalpy would be $\Delta H = -726.5 * -1 = 726.5 kJ$