Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises: 5.43c


15.664 grams of MgO

Work Step by Step

Looking at the thermochemical equation, we see that for an enthalpy change of -1204 kJ, that 2 moles of MgO are produced. Therefore, to find how much MgO is produced for a change of -234kJ we do the following: -234 kJ * (2 moles/-1204kJ) = 0.3887 moles MgO Then to find the grams produced we need the molar mass of MgO: Mg has a mass of 24.3050 g/mol O has a mass of 15.994 g/mol MgO has a mass of 40.299 g/mol Then we have: 0.3887 moles * (40.299 g/ 1 mole) = 15.664 grams
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