## Chemistry: The Central Science (13th Edition)

Given Ag+ + Cl- --&gt; AgCl $\Delta H = -65.5 kJ$, it means that for each mole of AgCl formed, 65.5 kJ of heat are released. To find $\Delta H$ for the production of 0.450 mol, it would be 0.450 * -65.5 kJ = -29.475 kJ