Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises: 5.45a

Answer

-29.475 kJ

Work Step by Step

Given Ag+ + Cl- --> AgCl $\Delta H = -65.5 kJ $, it means that for each mole of AgCl formed, 65.5 kJ of heat are released. To find $\Delta H$ for the production of 0.450 mol, it would be 0.450 * -65.5 kJ = -29.475 kJ
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