Answer
400. mL of that solution contains 40.0 g of $KOH$.
Work Step by Step
1. Identify the conversion factors:
- Since the $KOH$ solution is 10.0% (m/v):
10.0 g (Solute) = 100 mL (Solution)
So: $\frac{10.0 \space g \space (Solute)}{100 \space mL \space (Solution)}$ and $\frac{100 \space mL \space (Solution)}{10.0 \space g \space (Solute)}$
2. Calculate the volume of that solution that contains 40.0 g of $KOH$:
$40.0 \space g \space (Solute) \times\frac{100 \space mL \space (Solution)}{10.0 \space g \space (Solute)} = 400. \space mL \space (Solution)$
