Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 9 - Section 9.4 - Concentrations of Solutions - Questions and Problems - Page 301: 9.37c

Answer

There are necessary 25.0 mL of acetic acid to prepare 250. mL of that solution.

Work Step by Step

1. Identify the conversion factors: - Since the acetic acid solution is 10.0% (v/v): 10.0 mL (Solute) = 100 mL (Solution) So: $\frac{10.0 \space mL \space (Solute)}{100 \space mL \space (Solution)}$ and $\frac{100 \space mL \space (Solution)}{10.0 \space mL \space (Solute)}$ 2. Calculate the volume of solute needed to prepare 250. mL of that solution: $250. \space mL \space (Solution) \times \frac{10.0 \space mL \space (Solute)}{100 \space mL \space (Solution)} = 25.0 \space mL \space (Solute)$
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