Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 9 - Section 9.4 - Concentrations of Solutions - Questions and Problems - Page 301: 9.41a

Answer

20. g of mannitol are given to the patient in 1 hour.

Work Step by Step

1. Identify the conversion factors: - Since the mannitol solution is 20.% (m/v): 20. g (Solute) = 100 mL (Solution) So: $\frac{20. \space g \space (Solute)}{100 \space mL \space (Solution)}$ and $\frac{100 \space mL \space (Solution)}{20. \space g \space (Solute)}$ 2. Calculate the mass of solute needed to prepare 100. mL of that solution: $100. \space mL \space (Solution) \times \frac{20. \space g \space (Solute)}{100 \space mL \space (Solution)} = 20. \space g \space (Solute)$ 3. One 100. mL solution is given every hour. Therefore, in 1 hour, one 20.% (m/v) mannitol solution is given to the patient, which has 20. g of mannitol.
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