Answer
1.50 L of that $KBr$ solution has 3.00 moles of $KBr$.
Work Step by Step
1. Since the molarity of that solution is equal to $ 2.00 \space M \space KBr$:
$1 \space L \space solution = 2.00 \space moles \space KBr$
$\frac{1 \space L \space solution}{ 2.00 \space moles \space KBr} $ and $\frac{ 2.00 \space moles \space KBr}{1 \space L \space solution}$
2. Use the conversion factors to calculate the volume of that solution that has 3.00 moles $KBr$:
$3.00 \space moles \space KBr \times \frac{1 \space L \space solution}{ 2.00 \space moles \space KBr} = 1.50 \space L \space solution$
