Answer
There are necessary 34 mL of isopropyl alcohol to prepare 225 mL of that solution.
Work Step by Step
1. Identify the conversion factors:
- Since the isopropyl alcohol solution is 15% (v/v):
15 mL (Solute) = 100 mL (Solution)
So: $\frac{15 \space mL \space (Solute)}{100 \space mL \space (Solution)}$ and $\frac{100 \space mL \space (Solution)}{15 \space mL \space (Solute)}$
2. Calculate the volume of solute needed to prepare 225 mL of that solution:
$225 \space mL \space (Solution) \times \frac{15 \space mL \space (Solute)}{100 \space mL \space (Solution)} = 34 \space mL \space (Solute)$
