Answer
See graphs.
Vertical asymptote: $x=2$
Work Step by Step
1. We graph both functions on the same set of axes as shown in the figure.
2. We can identify the vertical asymptote as $x=2$
3. An overview of both functions shows that they have the same end behavior.
Extra:
Use synthetic division as shown, we can get $f(x)=x^2+\frac{16}{x-2}$, and its end behavior follows
the function as its quotient.
