Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.6 - Rational Expressions - 3.6 Exercises - Page 309: 53

Answer

x-intercept: (-2,0) (1,0) y-intercept: (0, 1/6) Vertical Asymptote: x=-4, 3 Domain: (-∞, -4) U (-4, 3) U (3, ∞) Horizontal Asymptote: y=1 Range: (-∞, 1) U (1, ∞) See graph below

Work Step by Step

$r(x)=\frac{(x-1)(x+2)}{(x+4)(x-3)}$ $(x-1)(x+2) = 0$ x = 1, -2 x-intercept: (1,0) (-2, 0) y-intercept is the ratio of the constants, which is -2/ -12 = 1/6 Thus, the y-intercept is at (0, 1/6) Vertical asymptotes are when the denominator is equal to 0 $(x+4)(x-3) = 0$ x = -4, 3 So, domain is from (-∞, -4) U (-4, 3) U (3, ∞) Horizontal asymptote is the ratio of the constants of the leading term (with equal degree) 1 / 1 = 1 Thus, the horizontal asymptote is at y=1 So the range is from (-∞, 1) U (1, ∞)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.