Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.6 - Rational Expressions - 3.6 Exercises - Page 309: 67

Answer

common factor $x+1$ x-intercept=3 y-intercept=9 no asymptotes. domain: $(-\infty,-1)\cup(-1,\infty)$ range: $[0,\infty)$

Work Step by Step

1. Use synthetic division as shown in the figure, we can factorize the numerator as $(x+1)(x^2-6+9)=(x+1)(x-3)^2$, thus we can identify that $x+1$ is a common factor of the numerator and the denominator, and a hole is at $(-1,16)$ 2. We can identify the following from the function: Let $y=0$, we get x-intercept=3 Let $x=0$, we get y-intercept=9 There are no asymptotes. 3. The graph of the rational function is shown in the figure and we can find domain: $(-\infty,-1)\cup(-1,\infty)$ range: $[0,\infty)$
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