Answer
$-1,0,\frac{13\pm\sqrt {29}}{12}$
Work Step by Step
$P(x)=x(6x^3-7x^2-8x+5)$
Test $-1, P(-1)=(-1)(-6-7+8+5)=0$
Use synthetic division as shown:
$P(x)=x(x+1)(6x^2-13x+5)$
The zeros are $-1,0,\frac{13\pm\sqrt {29}}{12}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.4 - Real Zeros of Polynomials - 3.4 Exercises - Page 284: 84
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