Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 73

Answer

$x = -\frac{2}{3}$

Work Step by Step

$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$ $9x^2+12x+4= 0$ Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$ $9x^2+12x+4$ $a = 9, b = 12, c = 4$ $x = \frac{-(12) \pm \sqrt {(12)^2- 4(9 \times 4)}}{2(9)}$ $x = \frac{-12 \pm \sqrt {144- 144}}{18}$ $x = \frac{-12 \pm \sqrt {0}}{18}$ $x = \frac{-12}{18}$ $x = -\frac{2}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.