Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 57: 82

Answer

This equation has no real solutions.

Work Step by Step

$3x^{2}=6x-9$ Take all terms to the left side: $3x^{2}-6x+9=0$ The formula for the discriminant is $D=b^{2}-4ac$. For this equation, $a=3$, $b=-6$ and $c=9$. Substitute the known values in the formula: $D=(-6)^{2}-4(3)(9)=36-108=-72$ Since $D\lt0$, this equation has no real solutions.
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