Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 67

Answer

$x_1 = 7, x_2 = 6$

Work Step by Step

$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$ $x^2-13x+42$ Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$ $1x^2-13x+42$ $a = 1, b = -13, c = 42$ $x = \frac{-(-13) \pm \sqrt {(-13)^2- 4(1 \times 42)}}{2(1)}$ $x = \frac{13 \pm \sqrt {169- 168}}{2}$ $x = \frac{13 \pm \sqrt {1}}{2}$ $x_1 = \frac{13+1}{2}, x_2 = \frac{13-1}{2}$ $x_1 = \frac{14}{2}, x_2 = \frac{12}{2}$ $x_1 = 7, x_2 = 6$
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