Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 69

Answer

$x_1 = 1, x_2 = -\frac{3}{2}$

Work Step by Step

$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$ $2x^2+x-3$ Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$ $2x^2+1x-3$ $a = 2, b = 1, c = 3$ $x = \frac{-(1) \pm \sqrt {(1)^2- 4(2 \times -3)}}{2(2)}$ $x = \frac{-1 \pm \sqrt {1+24}}{4}$ $x = \frac{-1 \pm \sqrt {25}}{4}$ $x_1 = \frac{-1+5}{4}, x_2 = \frac{-1 - 5}{4}$ $x_1 = \frac{4}{4}, x_2 = \frac{-6}{4}$ $x_1 = 1, x_2 = -\frac{3}{2}$
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