Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 70

Answer

$x_1 = -1, x_2 = -\frac{4}{3}$

Work Step by Step

$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$ $3x^2+7x+4$ Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$ $3x^2+7x+4$ $a = 3, b = 7, c = 4$ $x = \frac{-(7) \pm \sqrt {(7)^2- 4(3 \times 4)}}{2(3)}$ $x = \frac{-7 \pm \sqrt {49- 48}}{6}$ $x = \frac{-7 \pm \sqrt {1}}{6}$ $x_1 = \frac{-7+1}{6}, x_2 = \frac{-7-1}{6}$ $x_1 = \frac{-6}{6}, x_2 = \frac{-8}{6}$ $x_1 = -1, x_2 = -\frac{4}{3}$
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