Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises: 74

Answer

$x=\frac{1}{2}$

Work Step by Step

$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$ $4x^2-4x+1=0$ Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$ $4x^2-4x+1$ $a = 4, b = -4, c = 1$ $x = \frac{-(-4) \pm \sqrt {(-4)^2- 4(4 \times 1)}}{2(4)}$ $x = \frac{4 \pm \sqrt {16- 16}}{8}$ $x = \frac{4 \pm \sqrt {0}}{8}$ $x= \frac{4}{8}$ $x=\frac{1}{2}$
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