## Precalculus: Mathematics for Calculus, 7th Edition

The solutions of the equation $x^{2} +3x-4=0$ are x=1,-4
1. Factor the equation: The factors are (x−1) and (x+4) because −1×4 = -4 (the c value in $a^2+bx+c$ and -1+4 =3, the b value. 2. Set the factors equal to zero: $x-1 =0$ and $x+4=0$ 3. Solve: $x=1,-4$